Powerball odds and
probabilities for the Powerball Jackpot. How to calculate
these Powerball odds. Jackpot split probabilities including
return on investment calculations.
Updated for
the 69/26 Game
Concise Table of Powerball
Odds (Mathematical derivation below)
Ticket
Matches
Payout
Odds
Probability
--------------------------------------------------------------------
5 White +
PB
Jackpot 1 in
292,201,338.00
0.000000003422
5 White No PB
1,000,000 1 in
11,688,053.52
0.00000008556
4 White +
PB
50,000 1 in
913,129.18
0.000001095
4 White No
PB
100 1 in
36,525.17
0.00002738
3 White +
PB
100 1 in
14,494.11
0.00006899
3 White No
PB
7
1 in
579.76
0.001725
2 White +
PB
7
1 in
701.33
0.001426
1 White +
PB
4
1 in
91.98
0.01087
0 White +
PB
4
1 in
38.32
0.02609
Win something
Variable 1 in
24.87
0.0402
Game Rules
The numbers picked for the prizes consist of 5
white balls picked at random from a drum that holds 69 balls
numbered from 1 to 69. The Powerball number is a single ball
that is picked from a second drum that has 26 numbers ranging
from 1 to 26. If the results of these random number selections
match one of the winning combinations on your lottery ticket,
then you win something.
You can also buy a “Power Play” option. The
multipliers in the 69/26 Power Play game increase the payout
amounts for the non-jackpot prizes as shown in the “Power Play
Option” section. (Scroll down the page.)
In the game version that began as of Jan. 15, 2012, it
costs $2 to buy a ticket instead of the previous $1. The Power
Play option costs another $1; and as noted above, the payout
amounts have been changed.
Game Rules
for the new Powerball game that went into effect for the
Oct. 7, 2015 game.
As “game players” (“suckers”) woke up to the fact
that they were throwing money away trying to win the old 59/35
game, Powerball ticket sales slumped. Thus Powerball
officials changed the game rules again to try to recruit
more people to throw away their money.
The new game is designed to “engineer” bigger
jackpots. The mechanism involved was to make it even more
difficult to win. Thus funds that previously had been paid out
to “millionaire” winners will now be retained until a possible
“billionaire” figure is reached.
In the old version of the game, the chance of
winning the jackpot was one chance in COMBIN(59,5) x
COMBIN(35,1) = 175,223,510. The new version of the game has 69
balls in one bin and 26 in the other. Thus the chance of
winning the new game is 1 chance in COMBIN(69,5) x
COMBIN(26,1) = 292,201,338. In practical terms, it would
appear likely that few people will buy tickets for most
jackpots, but buying frenzies will develop for large jackpots.
(With the resulting prize split several ways.)
Imagine lining up baseballs (A standard baseball
is about 2.9 inches in diameter.) in a row for the 2,998.68
highway miles from Boston to Los Angeles (Mapquest). It would
take about 65,515,988 baseballs. Then randomly designate one
of these baseballs as a lucky “winner” baseball.
Imagine driving for days past this row of
millions and millions of baseballs. Then stop and pick up a
random baseball. The chance of a random ticket winning the new
Powerball is less than one fourth the chance of picking the
winning baseball.
The phrase “There's a sucker born every minute”
comes to mind. (Falsely attributed to P. T. Barnum
https://en.wikipedia.org/wiki/There's_a_sucker_born_every_minute
)
In any combinatorics problem where all possible
outcomes are equally likely, the probability of a successful
outcome is determined by finding the number of successful
combinations, and then dividing by the total number of all
combinations. There are nine possible configurations that will
win something in the Powerball Lottery. For each of these, the
probability of winning equals the number of winning
combinations for that particular configuration divided by the
total number of ways the Powerball numbers can be picked.
Powerball Total Combinations
Since the total number of combinations for
Powerball numbers is used in all the calculations, we will
calculate it first. The number of ways 5 numbers can be
randomly selected from a field of 69 is: COMBIN(69,5) =
11,238,513. (See the
math
notation page or Help in Microsoft's Excel for more
information on “COMBIN”).
For each of these 11,238,513 combinations there
are COMBIN(26,1) = 26 different ways to pick the Powerball
number. The total number of ways to pick the 6 numbers is the
product of these. Thus, the total number of equally likely
Powerball combinations is 11,238,513 x 26 = 292,201,338. We
will use this number for each of the following calculations.
Jackpot probability/odds (Payout varies)
The number of ways the 5 numbers on your lottery
ticket can match the 5 white balls is COMBIN(5,5) = 1. The
number of ways your Powerball number can match the single
Powerball number is: COMBIN(1,1) = 1. The product of these is
the number of ways you can win the Jackpot: COMBIN(5,5)
x COMBIN(1,1) = 1. The probability of success is thus:
1/292,201,338 = 0.000000003422297813+. If you express this as
“One chance in ???”, you just divide “1” by the
0.000000003422297813+, which yields “One chance in
292,201,338”.
Match all 5 white balls but not the Powerball
(Payout = $1,000,000)
The number of ways the 5 numbers on your lottery
ticket can match the 5 white balls is COMBIN(5,5) = 1. The
number of ways your Powerball number can match any of the 25
losing Powerball numbers is: COMBIN(25,1) = 25. (Pick any of
the 25 losers.) Thus there are COMBIN(5,5) x COMBIN(25,1) = 25
possible combinations. The probability for winning $1,000,000
is thus 25/292,201,338 ~= 0.00000008556 or “One chance in
11,688,053.52”.
Match 4 out of 5 white balls and match the
Powerball (Payout = $50,000)
The number of ways 4 of the 5 winning numbers on
your lottery ticket can match the 5 white balls is COMBIN(5,4)
= 5. The number of ways the losing white number on your ticket
can match any of the 64 losing white numbers is COMBIN(64,1) =
64. The number of ways your Powerball number can match
the single Powerball number is: COMBIN(1,1) = 1. The product
of these is the number of ways you can win this
configuration: COMBIN(5,4) x COMBIN(64,1) x COMBIN(1,1)
= 320. The probability of success is thus:
320/292,201,338 ~= 0.000001095 or “One chance in
913,129.18”.
Match 4 out of 5 white balls but not match the
Powerball (Payout = $100)
The number of ways 4 of the 5 winning numbers on
your lottery ticket can match the 5 white balls is COMBIN(5,4)
= 5. The number of ways the losing white number on your ticket
can match any of the 64 losing numbers is COMBIN(64,1) =
64. The number of ways your Powerball number can miss
matching the single Powerball number is: COMBIN(25,1) = 25.
The product of these is the number of ways you can win this
configuration: COMBIN(5,4) x COMBIN(64,1) x COMBIN(25,1)
= 8,000. The probability of success is thus: 8,000/292,201,338
~= 0.00002738 or “One chance in 36,525.17”.
Match 3 out of 5 white balls and match the
Powerball (Payout = $100)
The number of ways 3 of the 5 winning numbers on
your lottery ticket can match the 5 white balls is COMBIN(5,3)
= 10. The number of ways the 2 losing white numbers on your
ticket can match any of the 64 losing white numbers is
COMBIN(64,2) = 2,016. The number of ways your Powerball
number can match the single Powerball number is: COMBIN(1,1) =
1. The product of these is the number of ways you can win this
configuration: COMBIN(5,3) x COMBIN(64,2) x COMBIN(1,1)
= 20,160. The probability of success is thus:
20,160/292,201,338 ~= 0.00006899 or “One chance in 14,494.11”.
Match 3 out of 5 white balls but not match the
Powerball (Payout = $7)
The number of ways 3 of the 5 winning numbers on
your lottery ticket can match the 5 white balls is COMBIN(5,3)
= 10. The number of ways the 2 losing white numbers on your
ticket can match any of the 64 losing numbers is COMBIN(64,2)
= 2,016. The number of ways your Powerball number can
miss matching the single Powerball number is: COMBIN(25,1) =
25. The product of these is the number of ways you can win
this configuration: COMBIN(5,3) x COMBIN(64,2) x
COMBIN(25,1) = 504,000. The probability of success is thus:
504,000/292,201,338 ~= 0.001725 or “One chance in 579.76”.
Match 2 out of 5 white balls and match the
Powerball (Payout = $7)
The number of ways 2 of the 5 winning numbers on
your lottery ticket can match the 5 white balls is COMBIN(5,2)
= 10. The number of ways the 3 losing white numbers on your
ticket can match any of the 64 losing white numbers is
COMBIN(64,3) = 41,664. The number of ways your Powerball
number can match the single Powerball number is: COMBIN(1,1) =
1. The product of these is the number of ways you can win this
configuration: COMBIN(5,2) x COMBIN(64,3) x COMBIN(1,1)
= 416,640. The probability of success is thus:
416,640/292,201,338 ~= 0.001426 or “One chance in 701.33”.
Match 1 out of 5 white balls and match the
Powerball (Payout = $4)
The number of ways 1 of the 5 winning numbers on
your lottery ticket can match the 5 white balls is COMBIN(5,1)
= 5. The number of ways the 4 losing white numbers on your
ticket can match any of the 64 losing white numbers is
COMBIN(64,4) = 635,376. The number of ways your
Powerball number can match the single Powerball number is:
COMBIN(1,1) = 1. The product of these is the number of ways
you can win this configuration: COMBIN(5,1) x
COMBIN(64,4) x COMBIN(1,1) = 3,176,880. The probability of
success is thus: 3,176,880/292,201,338 ~= 0.01087 or “One
chance in 91.98”.
Match 0 out of 5 white balls and match the
Powerball (Payout = $4)
The number of ways 0 of the 5 winning numbers on
your lottery ticket can match the 5 white balls is COMBIN(5,0)
= 1. The number of ways the 5 losing white numbers on your
ticket can match any of the 64 losing white numbers is
COMBIN(64,5) = 7,624,512. The number of ways your
Powerball number can match the single Powerball number is:
COMBIN(1,1) = 1. The product of these is the number of ways
you can win this configuration: COMBIN(5,0) x
COMBIN(64,5) x COMBIN(1,1) = 7,624,512. The probability of
success is thus: 7,624,512/292,201,338 ~= 0.02609 or “One
chance in 38.32”.
Probability of winning something
If we add all the ways you can win something we get:
1 + 25 + 320 + 8,000 + 20,160 + 504,000 + 416,640 + 3,176,880
+ 7,624,512 = 11,750,538. If we divide this number by
292,201,338, we get .04021+ as a probability of winning
something. 1 divided by 0.04021- yields “One chance in
24.87” of winning something.
Probability of not matching anything
Match 0 out of 5 white numbers and not match the Powerball
There are 292,201,338 possible outcomes
to the game, Of these (as noted above) there are 1 + 25 + 320
+ 8,000 + 20,160 + 504,000 + 416,640 + 3,176,880 + 7,624,512 =
11,750,538 ways of winning something - which leaves
292,201,338 - 11,750,538 = 280,450,800 ways of not winning
anything. The probability that a random ticket will not win
anything is thus 280,450,800/292,201,338 = 0.9598 or about 24
out of 25.
Probability
of multiple winning tickets (multiple winners) given “N”
tickets in play
(Note: All calculations assume that the numbers on any given
ticket are picked randomly. In practice, many people pick
numbers based on family birthdays, etc., and thus many tickets
will have a preponderance of low numbers. As a consequence,
the probabilities of a single Jackpot winner will be somewhat
lower and the probabilities of no winner or multiple winners
will tend to be slightly higher than the numbers shown below.
Also if the numbers picked in the drawing are clustered at the
high end of the 1 - 69 range, there will tend to be relatively
less “partial match” winners. The reverse will hold true if
the drawing numbers cluster in the low end of the number
range.)
The above chart shows the probabilities of “No
Winners”, “One Winner”, and “Two or more Winners” for various
numbers of tickets in play.
Each entry in the following table shows the
probability of "K" tickets holding the same winning Jackpot
combination given that "N" tickets are in play for a given
Powerball game. It is assumed that the number selections on
each ticket are picked randomly. For example, if 100,000,000
tickets are in play for a Powerball game, then there is a
0.0416 probability that exactly two of these tickets will have
the same winning combination.
(Note: You can get a rough estimate of the number
of tickets in play as follows. If the preceding Powerball game
had no Jackpot winner, the number of tickets in play is
approximately equal to the dollar increase in the annuity
Jackpot. For example, if the preceding game had an annuity
payout amount of $350,000,000 and the current game has an
annuity payout amount of $400,000,000, then there are about
400,000,000 - 350,000,000 = 50,000,000 tickets in play for the
current game. (Each ticket sold for $2.) A history of these
past jackpot amounts (subtract about 50 % from the stated
jackpot amount to get the cash payout) can be seen at:
http://www.lottoreport.com/ticketcomparison.htm)
The following table gives the probabilities that exactly "K"
tickets will share a Jackpot given that there are "N" tickets
in play.
“N”
Number
“K”
of
tickets Number
of tickets holding the Jackpot combination
in
play
0
1
2
3
4
5 6
---------------------------------------------------------------------
100,000,000 0.7102
0.2430 0.0416 0.0047 0.0004
0.0000 0.0000
200,000,000 0.5044 0.3452
0.1181 0.0270 0.0046 0.0006 0.0001
300,000,000 0.3582 0.3678
0.1888 0.0646 0.0166 0.0034 0.0006
400,000,000 0.2544 0.3482
0.2383 0.1088 0.0372 0.0102 0.0023
500,000,000 0.1807 0.3091
0.2645 0.1509 0.0645 0.0221 0.0063
600,000,000 0.1283 0.2634
0.2705 0.1851 0.0950 0.0390 0.0134
700,000,000 0.0911 0.2183 0.2615
0.2088 0.1250 0.0599 0.0239
800,000,000 0.0647 0.1772 0.2425
0.2213 0.1515 0.0830 0.0379
Any entry in the table can be calculated using the following
equation:
Prob. = COMBIN(N,K) x (Pwin^K) x (Pnotwin^(N-K))
Where:
N = Number of tickets in play
K = Number of tickets holding the Jackpot combination
Pwin = Probability that a random ticket will win ( = 1 /
292,201,338 = 0.00000000342)
Pnotwin = (1.0 - Pwin) = 0.99999999658
COMBIN(N,K) = number of ways to select K items from a
group of N items
x = multiply terms
^ = raise to power (e.g. 2^3 = 8 )
Sample
Calculation to Find the Expected Ticket Value
Considering the Number of Tickets that are in Play
For this example we will assume the cash value of
the Jackpot is $600,000,000 and there are 200,000,000 tickets
in play for the current game. Probability values are from the
“200,000,000” row above.
The first calculation is: “What is the
probability that the jackpot will be won?” This is simply
(1.00 – the probability that no one will win) = 1.00 – 0.5044
= 0.4956. Thus the expected jackpot payout by the lottery is
$600,000,000 times 0.4956 = $297,382,360.
If there are 200,000,000 tickets in play, then we
divide the $297,382,360 by 200,000,000 to get an average
jackpot payout per ticket of $1.49. The other smaller prizes
add $0.3199 to this amount to give an "expected before tax,
cash value of $1.81.
These calculations can be used to form a table
that shows the expected return per ticket (
= expected value per ticket). For example if the cash
value of the jackpot is $600,000,000 and there are 200,000,000
tickets in play, then the ticket’s expected value is
$1.81.
The following table shows the "Expected Before
Taxes Value" (includes $0.3199 for the smaller prizes) of a
$2.00 ticket.
Nbr. Tickets
In
Play <
- Cash (not annuity) Jackpot Size in
Millions - >
In
Millions 100 200
300 400 500
600 700 800 900
1000
-----------------------------------------------------------------------
100 0.61
0.90
1.19 1.48 1.77 2.06 2.35
2.64 2.93 3.22
200
0.57 0.82 1.06 1.31 1.56
1.81 2.05 2.30 2.55 2.80
300
0.53 0.75 0.96 1.18 1.39
1.60 1.82 2.03 2.25 2.46
400
0.51 0.69 0.88 1.07 1.25
1.44 1.62 1.81 2.00 2.18
500
0.48 0.65 0.81 0.98 1.14
1.30 1.47 1.63 1.79 1.96
600
0.47 0.61 0.76 0.90 1.05
1.19 1.34 1.48 1.63 1.77
700
0.45 0.58 0.71 0.84 0.97
1.10 1.23 1.36 1.49 1.62
800
0.44 0.55 0.67 0.79 0.90
1.02 1.14 1.26 1.37 1.49
900
0.43 0.53 0.64 0.74 0.85
0.96 1.06 1.17 1.27 1.38
1000 0.42 0.51
0.61 0.71 0.80 0.90 1.00
1.09 1.19 1.29
We can also see what happens to the expected
value of a ticket if a buying frenzy should develop at this
point. Let’s assume that 300 million more tickets are sold. At
$2,00 per ticket, the lottery takes in $600 million. 1/2 of
this goes into the total prize pot. (1/3 for the jackpot
and 1/6 for the smaller prizes.) The jackpot is now
worth $600 million plus $200 million = $800 million.
Thus the game is transformed into 500 million
tickets in play for a cash jackpot that is now worth $800
million. If we follow the 500-million row to the right until
we reach the $800 million column, we find an expected
cash value of $1.63. The buying frenzy has reduced the
expected value of a ticket from $1.81 to $1.63.
Power Play
Option (assume 10x option)
The Powerball game includes an optional “Power
Play”. If you spend an extra $1 for the “Power Play”, then the
low order prizes are increased as shown in the following
table.
The Power Play has a random multiplier as per the following
table.
Multiplier
times
Multiplier
Probability
Probability
2X
24/43
1.1163
3X
13/43
0.9070
4X
3/43
0.2791
5X
2/43
0.2326
10X
1/43
0.2326
Sum
2.7674
Thus the expected average total payout if
you pay for the Power Play option is 2.7674 times the original
payouts. Since you would get the original payouts without
paying for the Power Play option, the net value of the Power
Play is the increase in payout amounts. This increase in
payout amounts is: 2.7674 – 1.0 = 1.7674 times the original
payout amounts. We can use this 1.7674 multiplier to calculate
the expected return if you pay the extra $1.00 for the Power
Play option.
Payout
Increased
Exp.
Val
Without
Payout With Prob.
of Expected
After
Match
Power
Play Power
Play of
result
Value Taxes
5 for 5 not PB
1,000,000 1,000,000
8.556E-08
0.0856 0.0513
4 for 5 with PB
50,000 88,372.09
1.095E-06
0.0968 0.0581
4 for 5 not
PB
100
176.74
2.738E-05
0.0048 0.0048
3 for 5 with
PB
100
176.74
6.899E-05
0.0122 0.0122
3 for 5 not
PB
7
12.37
0.0017248
0.0213 0.0213
2 for 5 with
PB
7
12.37
0.0014259
0.0176 0.0176
2 for 5 not
PB
4
7.07
0.0108722
0.0769 0.0769
1 for 5 with
PB
4
7.07
0.0260934
0.1845 0.1845
Total
0.4997
0.4268
Each row shows the combination involved, the payout amount
without including the Power Play, the increased payout amount
with Power Play included, the probability of the particular
output, the expected value for this contribution, and the
expected value after 40% is deducted for federal, state, and
local taxes. The “Expected Value” is the increase in payout
amount times the probability. The total line shows that for
each $1.00 that you spend for a Power Play option, you can
expect to get back only $0.4997. Taxes reduce this long term
expected payout to less than $0.43 for each dollar you pay for
the Power Play.
An analysis for Power Play without the 10X option shows
the same approximate $0.50 per $1.00 spent return.
Return on
Investment
It is interesting to calculate what the long term
expected return is for each $2.00 lottery ticket that you buy.
The first task is to construct a table where each
row lists the winning combination, the payout, the probability
of this payout, and the contribution to the expected return
(Equals payout times probability.) The probabilities are the
same ones we derived earlier. A $200,000,000 cash payout
(decline the annuity) is assumed for the Jackpot. (Would be
your portion of a shared Jackpot.)
Combination
Payout
Probability
Contribution
---------------------------------------------------------
5 White + PB $200,000,000
3.42230E-09 $0.6845
5 White No PB
1,000,000
8.55574E-08 0.0856
4 White +
PB
50,000
1.09514E-06 0.0548
4 White No
PB
100 2.73784E-05
0.0027
3 White +
PB
100
6.89935E-05
0.0069
3 White No
PB
7
0.001724838
0.0121
2 White +
PB
7
0.001425866
0.0100
1 White +
PB
4
0.010872229
0.0435
PB
4
0.026093351
0.1044
Total
0.040213840
1.0043
Total for last 6
rows
0.1796
(Used for after tax calculation)
Thus, for each $2.00 that you spend for Powerball
tickets, you can expect to get back about $1.0043. Of course
you get to pay taxes on any large payout, so your net return
is even less.
Expected
after tax return on your $2.00 ticket investment
when a huge Jackpot is in play
While the above calculation represents an average
Powerball game, we might ask what the expected after tax
return on your investment might be if a huge Jackpot exists.
The following analysis assumes the annuity value of the
Jackpot is $2 Billion (that’s a “B”) and there are 600 million
tickets in play. The cash value for any Jackpot is about
one-half the annuity value which brings the real value down to
$1,000,000,000. All prizes of $50,000 and above are reduced
40% to allow for federal and state taxes. Don’t forget that a
large prize will throw you into a top tax bracket.
First, we check the expected value of a ticket in
the table that we calculated earlier. Follow the 600-million
row until you come to the $1,000 million column. The expected
cash value of the ticket is $1.77.This included $0.3199 for
the smaller prizes so $0.3199 has to be subtracted back out.
This leaves $1.45 for the Jackpot component. However, this has
to be reduced by 40% for taxes. This leaves an expected after
tax value of the jackpot of $0.8717.
Next we include the after tax expected value from the
two >= $50,000 prizes. This equals 0.0856+ 0.0548 = 0.1403
less 40% for taxes to give us an additional $0.0842.
Finally, we add in the expected value for the
“Total for last 6 rows” This adds another 0.1796 for our
expected return. The sum of these three numbers is the
expected after tax return for this particular combination.
$0.8717 + $0.0842 + $ 0.1796 = $1.1355 expected after tax
return for each $2 that you spend per ticket.
General Rules
for the Expected Value of a Ticket
The expected value of a ticket will vary
depending on how many tickets are in play (shared jackpot
calculations) as well as the payout rules for a game. If the
number of tickets in play were proportional to the size of the
jackpot, then the expected value of a ticket would
asymptotically approach (gradually approach but never quite
reach) some fixed value. (Proportional increase = If the size
of the jackpot doubled, then the number of tickets in play
would double.)
In practice, buying frenzies develop when a large
jackpot exists – particularly if the quoted jackpot is larger
than any previous jackpot. Thus the number of tickets in play
increases faster than a simple proportional increase. When
this happens, the expected value of a ticket will actually
decrease when huge jackpots exist. We saw this happen with the
very large “Billion dollar” jackpot in mid Jan. 2016. The more
the jackpot increases, the greater the buying frenzy. The
result is that the expected value of a ticket is actually
decreasing even though the quoted size of the jackpot is
increasing.
Thus the general shape of a graph plotting of the
“expected value” of a ticket will resemble the shape of the
red line in the graph shown earlier.
This principle of decreasing “expected value” can
be illustrated by 2 simple examples. We will assume that the
only prize is the jackpot. Also 1/3 of any new money that is
spent on tickets is used to increase the jackpot. (This is the
way that Powerball is actually run.) In both cases we will
assume that a $1 billion cash value jackpot exists prior to
ticket purchases.
Example 1)
One ticket is purchased. Net proceeds to the
lottery are 1 x $2.00 = $2.00. 1/3 of this is 2 divided
by 3 = $0.67. This is added to the cash value of the lottery
which brings the jackpot up to $1,000,000,000.67. If only 1
ticket is in play, then no adjustment has to be made for
splitting the jackpot. The before tax expected value of the
ticket is the value of the jackpot divided by the number of
combinations. This becomes $1,000,000,000.67 divided by
292,201,338 = $3.42. This has to be reduced by 40% to get the
after tax expected value. $3.42 less 40% = $2.05. The expected
after tax value of the ticket is $2.05 - which would be
marginaly profitable.
Example 2)
One billion (1,000,000,000) tickets are
purchased. Net proceeds to the lottery are 1,000,000,000 x
$2.00 = $2,000,000,000.00. 1/3 of this is 2,000,000,000
divided by 3 = $666,666,666.67. This is added to the cash
value of the lottery which brings the jackpot up to
$1,666,666,666.67. There is a 0.9674 probability that at least
one winner will exist if 1,000,000,000 tickets in play. If
there are 1,000,000,000 tickets in play, then
the expected jackpot per ticket is $1.6123. The $1.6123
payout has to be reduced by another 40% to give an after tax
return. Thus brings the after tax expected share of the
jackpot down to $0.9674. You spent $2.00 for an expected
after tax return of $0.97.
Percentile
Expected Returns on Ticket Purchases
The average return per $ 2.00 ticket includes the
extremely low probability that you might win a large prize –
for example $50,000 or more. As a practical matter, it is
unlikely that you will ever buy enough tickets (fork out
enough money) to ever have much of a chance for any of the
large prizes. Thus it is probable that all you will ever get
back from your ticket purchases are piddling small amounts.
The percentages for these small amounts can
be calculated. The table below shows the percentage chances
for various “piddling returns”.
If you spend $2,000 to buy 1,000 tickets (1 ticket for each of
1,000 Powerball games), there is a:
49.67 % chance that you will get back $172 or less
59.94 % chance that you will get back $180 or less
69.98 % chance that you will get back $189 or less
79.76 % chance that you will get back $201 or less
90.08 % chance that you will get back $231 or less
94.97 % chance that you will get back $268 or less
97.98 % chance that you will get back $295 or less
99.00 % chance that you will get back $314 or less
99.50 % chance that you will get back $346 or less
99.88 % chance that you will get back $504 or less
Even if you buy 1,000 tickets, your chance of winning a
$50,000 or larger prize is less than 0.12 %.
2nd Thoughts
Government
statistics show there are about 1.7 automobile caused
fatalities for every 100,000,000 vehicle-miles. If you drive
one mile to the store to buy your lottery ticket and then
return home, you have driven two miles. Thus the probability
that you will join this statistical group is 2 x 1.7 /
100,000,000 = 0.000000034. This can also be stated as “One in
29,411,765-”. Thus, if you drive to the store to buy your
Powerball ticket, your chance of being killed (or killing
someone else) is about 10 times greater than the chance that
you will win the Powerball Jackpot.
Alternately, if you “played” Russian Roulette 100
times per day every day for 79 years with Powerball Jackpot
odds, you would have better than a 99% chance of surviving.
3rd Thoughts
A lottery is a “Zero-sum game”. What one group of
participants gains in cash, the other group of participants
must lose. If we made a list of all the participants in a
lottery, it might include:
1) Federal Government (Lottery winnings are taxable)
2) State Governments (Again lottery winnings are taxable)
3) State Governments (Direct share of lottery ticket sales)
4) Merchants that sell tickets (Paid by the lottery
organizers)
5) Lottery companies (Hint: They are not doing all this for
free)
6) Advertisers and promoters (Paid by the lottery companies)
7) Lottery ticket buyers (Buy lottery tickets and receive
payouts)
The winners in the above list are:
1) Federal Government
2) State Government (Taxes)
3) State Government (Direct share)
4) Merchants that sell tickets
5) Lottery companies
6) Advertisers and promoters
And the losers are:
(Mathematically challenged and proud of it)
Also please see the related calculations for
Mega
Millions
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