You might be thinking "What does
Einstein's special and general theories of relativity have
to do with a GPS system?" The answer is your GPS system
would not work if the engineers who designed and built your
GPS system had forgotten to include Einstein's equations in
their design.
We take it for granted that your $100 (or more)
GPS receiver will tell you where you are, nevermind which
direction you should go in order that you will arrive at
your intended destination. If you are hiking out in the
wilderness, you depend on your GPS to find your way back to
your car so you can get home. If you are taking a car trip,
you depend on your GPS to show you which roads to take when
you come to an intersection. If you are taking a
transoceanic airplane trip and the only thing you can see is
blue ocean water, you will be more comfortable if you
understand that the pilot can simply press a button to
eventually find an airport - specifically the airport that
matches what is on your ticket.
To tell you where you are, your GPS receiver
has to lock on to and receive information from at least four
GPS satellites. It will use these 4 satellites to solve 4
equations - that have 4 unknowns. These unknowns are:
your latitude, your longitude, your altitude, and the
difference in time between the clock in your GPS receiver
and the clocks in the 4 satellites. (It is the job of the
GPS satellites to keep their clocks in sync.) The satellites
in turn have to stay in sync with a ground control station.
The bad news is that even if you started with identical
clocks in your satellites and your ground control station,
once you put the satellites in orbit, they will "tick" at
different rates than the ground control station - and this
is where Einstein's equations come into play..
Einstein devised 2 theories of relativity.
Special relativity determines what happens to the relative
clock speeds between 2 clocks that are in relative motion to
each other. General relativity determines what happens to
the relative clock speeds between 2 clocks that are at
different heights/positions in a gravitational field. The
effects of both can be calculated.
The amount that GPS satellite clocks have to be
adjusted has been well discussed. For example see Real-World
Relativity: The GPS Navigation System . The above
article explains that because GPS satellites are moving in
orbit around the earth, their clocks will run about 7
millionths of a second per day slower then an identical
clock on the surface of the earth. Also, because the GPS
satellites are far above the earth's surface, their clocks
would run about 45 millionths of a second per day faster
than identical clocks on the surface of the earth. This
gives a net 45 - 7 = 38 millionths of a sec. gain per day.
What isn't given is details of how fast the GPS satellites
are moving, how high they are, how these numbers are
calculated, etc.
The table below will show these results and
give some idea how the data is calculated. The table also
shows what adjustments would have to be made to your
satellite clocks even if your GPS satellites were set up for
some other altitude. (Actual GPS satellites orbit at about
20,186 kilometers above the earth's surface)
For the results shown below, the author has assumed:
The speed of light in a vacuum = C =
299,792.458 km/sec.
The earth is a non rotating sphere with a radius of 6375.4
km.
The acceleration of gravity at the surface of this sphere
= 9.806650 meters/sec2
Velocity
at a given distance above the earth's surface is the
velocity needed for a satellite to have a circular orbit
at that distance.
Clock
Clock
Dist.from Dist.from Acceleration
Circular Escape
Slowdown in Slowdown in
Earth's Earth's of
gravity Orbital
Vel. at millionths of
millionths of
Surface in Center in at this
dist Velocity this
ht. a sec./day a sec/day
for
kilometers kilometers (in m/s^2)
in m/s. in m/s. for
Velocity escape vel.
-------------------------------------------------------------------------
0 6,375.4
9.806650 7.907.04
11,182.25
-30.05
-60.10
100
6,475.4 9.506099
7,845.75 11,095.57
-29.59
-59.18
200
6,575.4
9.219157 7,785.86
11,010.87
-29.14
-58.28
300
6.675.4
8.945013 7,727.32 10,928.09
-28.70 -57.40
400
6,775.4 8.682917 7,670.09
10,847.14 -28.28
-56.56
500
6,875.4 8.432175
7,614.10 10,767.97
-27.87 -55.73
600
6,975.4
8,192139 7,559.33 10,690.50
-27.47 -54.93
700
7,075.4 7.962209 7,505.72
10,614.69 -27.08
-54.16
800
7,175.4 7.741824
7,453.23 10,540.46
-26.70 -53.40
900
7,275.4 7.530465 7,401.83
10,467.77 -26.33
-52.67
1,000
7,375.4 7.327645 7,351.48
10,396.57 -25.98
-51.95
2,000
8,375.4 5.682304 6,898.66
9,756.18 -22.88
-45.75
3,000
9,375.4 4.534777
6,520.38 9,221.21
-20.44 -40.87
4,000
10,375.4 3,702762 6,198.20
8,765.57 -18.47
-36.93
5,000
11,375.4 3.080365 5.919.49
8.371.43 -16.84
-33.69
6,000
12,375.4 2.602658 5,675.29
8,026.07 -15.48
-30.96
7,000
13,375.4 2.228035
5,459.02 7,720.21
-14.32 -28.65
8,000
14,375.4 1.928838 5,265.72
7,446.85 -13.33
-26.66
9,000
15,375.4 1.686098 5.091.60
7,200.61 -12.46
-24.92
10,000 16,375.4
1.486455 4,933.69
6,977.29 -11.70
-23.40
20,000 26,375.4
0.572977 3,887.48
5,497.73 -7.26
-14.53
20,186 26,561.4
0.564981 3,873.85
5,478.44 -7.21
-14.43
30,000 36,375.4
0.301245 3,310.27
4,681.43 -5.27
-10.53
40,000 46,375.4
0.185336 2,931.73
4,146.09 -4.13
-8.26
50,000
56,375.4 0.125417
2,659.03
3,760.43
-3.40
-6.80
100,000
106,375.4 0.035225
1.935.74
2,737.55
-1.80
-3.60
384,400
390,775.4 0.002610
1.009.96
1,428.30
-0.49
-0.98
1,000,000
1,006,375.4
0.000394 629.34
890.03
-0.19
-0.38
1.0E7
1.0+E7
0.000004 199.59
282.26
-0.02
-0.04
1.0E8
1.0+E8
0.000000 63.13
89.28
-0.00
-0.00
1.0R9
1.0+E9
0.000000 19.96
28.23
-0.00
-0.00
Only earth is considered. Other astronomical
objects are ignored.
Accuracy is dependent upon starting assumptions.
Precision errors may exist in clock slowdown
calculations.
The total time speed-change in clocks in our actual GPS
system (about 20,186 km. above the earth's surface) =
Slowdown due to the velocity of the GPS satellites, plus
the (negative) slowdown due to the escape velocity at
the actual satellites' height, minus the (negative)
slowdown due to escape velocity at the earth's surface.
Mathematically this equals -7.21 +(negative)-14.43 -(a
negative) -60.10 = -7.21 -14.43 + 60.10 = about +38.46
millionths of a sec. per day.
How to calculate the above table.
Dist. from earth's surface in kilometers. Distance that a
satellite is above the surface of the hypothetical non
rotating surface of a spherical planet earth.
Dist. from earth's center in kilometers. Just add 6,375.4
kilometers to the above.
Acceleration due to gravity at this dist.
in m/s2. An acceleration due to gravity of
9.806650 meters per sec2. at the surface of a
non-rotating earth (radius = 6,375.4 km.) is assumed.
The acceleration at any distance from the center of the
earth is calculated by multiplying 9.806650 by: 6375.42 / Dist.
from earth's center in kilometers2.
For example: The acceleration due to gravity at the GPS
satellites' radius = 9.806650 x 6375.42 / 26561.42
= 0.564981 m/s2 .
Circular orbital velocity in Meters/sec.
is calculated.
This can be calculated by multiplying the acceleration of
gravity at that dist. by the dist to the center of the earth
in meters (Note that we use meters and not km), and then
take the square root of the result.
For our GPS satellites this calculation is:
Circular orbit vel. = Sqrt(0.564981 x 26561.4 x 1000.0)
(Don't forget km. to m)
= 3873.85 m/sec.
Escape Vel. in Meters/sec.
This is the minimum vel. needed to escape the earth's
gravity at this altitude
= vel. of a falling object if it fell from inf. to this
point.
Just multiply the circular orbital vel. by Sqrt(2)
For our GPS satellites: Escape vel. = Sqrt(2) x 3,873.85 =
5,478.44 m/sec.
Clock slowdown due to motion (vel.) of
satellite.
PerceivedRelativeTime = ClockAtRestInOuterSpace
* Sqrt(1.0 - SpeedOfClockSat2/C2)
= ClockAtRestInOuterSpace
* Sqrt(1.0 - (3873.852/2997924582))
(Watch for precision error)
Clock speed due to gravitational position
(escape velocity) of satellites
ClockAtSatPos (Do for both
earth suface and sat. height)
= ClockAtRestInOuterSpace * Sqrt(1.0 - EVatSat2/C2)
minus ClockAtRestInOuterSpace *
Sqrt(1.0 - EVatGround2/C2)
(EV = Escape vel. at relevant location)
(Watch for precision error)
Faster
than the speed of light?
A second subject also falls into the
realm of relativity. We might ask the questions:
"If an object falls into a black hole, can it fall faster
than the speed of light? Is there an 'Event Horizon' such
that beyond this limit, no information from a falling object
can escape?"
The answer to both questions is a resounding NO!
From Wikipedia: "Faster-than-light
(also FTL, superluminal or supercausal) travel and
communication are the conjectural propagation of matter or
information faster than the speed of light (c). The
special theory of relativity implies that only particles
with zero rest mass (i.e., photons) may travel at the
speed of light, and that nothing may travel faster."
"As
of the 21st century, according to current scientific
theories, matter is required to travel at
slower-than-light (also STL or subluminal) speed with
respect to the locally distorted spacetime region."
From the National Radio Astronomy Observatory
https://public.nrao.edu/ask/is-the-speed-of-light-changed-by-gravity/
Is the Speed of Light Changed by Gravity?
The short answer is no, the speed of light that you measure
locally is unchanged by gravity.
Einstein's famous equation states E = MC2.
This is actually a condensed form of the equation since M
(mass) is only implicitly given. If you expand the equation,
than it would look like:
E = MC2/ sqrt (1-V2/C2).
(V = velocity of the mass involved and C = velocity of
light.) Note what happens as V (Velocity) becomes closer to
the speed of light. If "V" approaches the speed of
light, then the denominator of the equation becomes
infinitely small, and the M (mass) of the equation becomes
infinitely large.
And this leads to another reason why a"Black
Hole" can not generate an event horizon that would pull in a
falling object at the speed of light. Assume an incoming
hydrogen atom was sucked in until it reached the speed of
light at an event horizon. According to E = MC2/
sqrt (1-V2/C2) the incoming hydrogen
atom would have an infinite mass - and an infinite
gravitational field. The infinite mass would pull in the
rest of the universe as fast as its gravitational field
could propagate outward. However, we are still all here
which implies that an infinite mass has never existed.
If you concentrated all the energy in the known
universe into the engine of a spaceship, you could not cause
the spaceship to reach the speed of light. Even though "all
the energy in the known universe" might be a very large
number, it is still a finite number.
We can investigate this phenomenon via the
equation of what happens when you add two or more large
speeds.
Is the net result:
speed = speed 1 plus speed 2? (Assume both speeds go in the
same direction.)
Nope. The approximation is reasonably OK at slow speeds, but
at very high speeds you have to use:
Net result of addition of speeds = (U + V) / (1 + U*V/C2)
U = speed of first object
V = speed of 2nd object
C = speed of light = 299,792.458 km/Sec.
For example, if you fall into a gravitational
field such that you would fall at 100,000 km/sec , and
then fall further such that you would think that you would
acquire an additional speed of another 100,000 km/sec., in
reality your speed becomes: (100,000 + 100,000) / (1 +
100,000*100,000/299,792.4582=
179,975.07km/sec
Then, assume that you fall another distance
thinking that you will gain another + 100,000 km/sec.. If
you use the addition equation again, you will instead have
reached 233,264.10 km/sec.
Repeating the process an arbitrary number of times
produces the following result:
100,000.00
179,975.07
233,264.10
264,591.64
281,668.91
290,596.33
295,161.25
297,469.08
298,629.12
299,210.52
299,501.50
299,647.02
299,719.77
299,756.13
299,774.30
299,783.38
299,787.92
299,790.19
299,791.33
299,791.89
299,792.18
299,792.32
299,792.39
299,792.42
299,792.44
299,792.45
299,792.45
299,792.46
299,792.46
299,792.46 km/sec.
You never reach the speed of light You could
use any other increment of speed increase and the result
would be the same. In all cases, you almost reach the
speed of light, but never quite make it. The only
difference would be the "how quickly that you almost reach
the speed of light but never reach it" would be the only
variable.
As a complicating factor, let's assume that
you can move either forward or backward at variable speeds
within a "gravitational black hole" and shine a powerful
flashlight out toward an observer spaceship that is
somewhere out of harms way. How fast would the light beam
be traveling at any (and all intermediate) point(s) while
it traveled from you to the distant spaceship?
Again, using the equation, let U be the speed
that light leaves the flashlight and V equals your speed
(either forward or backward)
Speed
of
Your
Flashlight beam
flashlight beam
Speed Speed at observer
U
V
Calculated Speed
299,792.46
0.00
299,792.46
299,792.46
60.00
299,792.46
299,792.46 10,000.00
299,792.46
299,792.46 100,000.00
299,792.46
299,792.46 250,000.00
299,792.46
299,792.46 299,792.45
299,792.46
299,792.46 400,000.00
299,792.46 (Impossible
but threw into the eq. for fun)
299,792.46
0.00
299,792.46 (Neg.means that you are
traveling(backwards)
299,792.46
(60.00)
299,792.46
299,792.46 (10,000.00)
299,792.46
299,792.46 (100,000.00)
299,792.46
299,792.46 (250,000.00)
299,792.46
299,792.46 (299,792.45)
299,792.46
299,792.46 (400,000.00)
299,792.46 (Impossible
but threw into the eq. for fun)
(Note. If you, the experimenter, tried this, and if you
sent light signals at defined intervals according to your
clock, there would be increasingly long periods in between
your increasingly red shifted light signals reaching your
(safe) observer, but your flashlight beam would always get
there.)
In conclusion. No matter what speed you are traveling at,
your flashlight beam always makes it out of the "black
hole" to the observer. The conjecture that a "black hole"
prevents information from escaping is erroneous.
Finally, consider the accretion disk of material falling
into a "black hole". Something that is originating in the
"black hole" is propagating outward to cause the inward
falling material to fall toward the "black hole". The word
"gravity" comes to mind. Thus the "black hole's"
gravitational field is able to escape from the "black
hole". So information is able to escape a black hole.
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